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0=9x^2+7x-18
We move all terms to the left:
0-(9x^2+7x-18)=0
We add all the numbers together, and all the variables
-(9x^2+7x-18)=0
We get rid of parentheses
-9x^2-7x+18=0
a = -9; b = -7; c = +18;
Δ = b2-4ac
Δ = -72-4·(-9)·18
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{697}}{2*-9}=\frac{7-\sqrt{697}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{697}}{2*-9}=\frac{7+\sqrt{697}}{-18} $
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